Scientific Measurements
Measurement - consist of a number and its corresponding unit
i.e. 2 minutes, 8000 millilitres, 4.5 light-years
I. English System of Measurement
i.e. inches, miles, gallons, pounds
II. Metric System, SI
> common language of all scientists
INCONVENIENT UNITS to use at all times
* meter, second, gram, etc.
Why?
i.e.
length of hair - meter is is too long for measuring length of hair
distance from Manila to Laguna - meter is too short for this distance
Metic Prefix - can make the base unit larger or smaller by adding the prefix before the base unit
link to metric prefix
3 units of Temperature:
1) Degrees Fahrenheit (°F)
2) Degrees Celsius
3) Kelvin (K)
Formulae for conversion
i.e. a recipe calls for roasting a cut of meat at 350 degrees Fahrenheit. What is the temperature in (a) Celsius and (b) Kelvin?
formula for (a) : °F to °C (°C = 5/9 [°F-32])
F = 350
C = 5/9 (350 - 32)
C = 5/9 (318)
C = 176.67
formula for (b) : K to °C ( K = °C +273)
K = 176.67 + 273
K = 449.67
2) O C to F
F = 9/5 C + 32
F = (9/5) 0 + 32
F = 0 + 32
F = 32
3) 300 K to F
K = 300
K = C +273
300 = C + 273
300 - 273 = C
27 = C
F = 9/5 C + 32
F = 9/5 (27) + 32
F = 48.6 + 32
F = 80.6
4) 273 K to C
K = 273
K = C + 273
273 = C + 273
273-273 = C
C= 0
i.e. 2 minutes, 8000 millilitres, 4.5 light-years
I. English System of Measurement
i.e. inches, miles, gallons, pounds
II. Metric System, SI
> common language of all scientists
INCONVENIENT UNITS to use at all times
* meter, second, gram, etc.
Why?
i.e.
length of hair - meter is is too long for measuring length of hair
distance from Manila to Laguna - meter is too short for this distance
Metic Prefix - can make the base unit larger or smaller by adding the prefix before the base unit
link to metric prefix
3 units of Temperature:
1) Degrees Fahrenheit (°F)
2) Degrees Celsius
3) Kelvin (K)
Formulae for conversion
°C to °F (°F = 9/5 °C + 32 )
K to °C ( K = °C +273)
°F to °C (°C = 5/9 [°F-32])
i.e. a recipe calls for roasting a cut of meat at 350 degrees Fahrenheit. What is the temperature in (a) Celsius and (b) Kelvin?
formula for (a) : °F to °C (°C = 5/9 [°F-32])
F = 350
C = 5/9 (350 - 32)
C = 5/9 (318)
C = 176.67
formula for (b) : K to °C ( K = °C +273)
K = 176.67 + 273
K = 449.67
2) O C to F
F = 9/5 C + 32
F = (9/5) 0 + 32
F = 0 + 32
F = 32
3) 300 K to F
K = 300
K = C +273
300 = C + 273
300 - 273 = C
27 = C
F = 9/5 C + 32
F = 9/5 (27) + 32
F = 48.6 + 32
F = 80.6
4) 273 K to C
K = 273
K = C + 273
273 = C + 273
273-273 = C
C= 0
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